최대 절전 모드 예외 : org.hibernate.AnnotationException : 엔티티에 지정된 식별자가 없습니다 : com..domain.idea.MAE_MFEView

최대 절전 모드 예외 : org.hibernate.AnnotationException : 엔티티에 지정된 식별자가 없습니다 : com..domain.idea.MAE_MFEView

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이 예외가 발생하는 이유는 무엇입니까?

package com.domain.idea;

import javax.persistence.CascadeType;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.JoinColumn;
import javax.persistence.OneToOne;
import javax.persistence.Table;

import org.hibernate.annotations.AccessType;

/**
 * object model for the view [InvestmentReturn].[vMAE_MFE]
 */
@Entity
@Table(name="vMAE_MFE", schema="InvestmentReturn")
@AccessType("field")
public class MAE_MFEView
{
    /**
     * trade property is a SuggestdTradeRecommendation object
     */
    @OneToOne(fetch = FetchType.LAZY , cascade = { CascadeType.PERSIST })
    @JoinColumn(name = "suggestedTradeRecommendationID")
    private SuggestedTradeRecommendation trade;

    /**
     * Most Adeverse Excursion value
     */
    private int MAE;

    public int getMAE()
    {
        return MAE;
    }

    /**
     * Most Favorable Excursion value
     */
    private int MFE;

    public int getMFE()
    {
        return MFE;
    }

    /**
     * @return trade property
     * see #trade
     */
    public SuggestedTradeRecommendation getTrade()
    {
        return trade;
    }
}

업데이트 : 코드를 다음과 같이 변경했습니다.

package com.domain.idea;

import javax.persistence.CascadeType;
import javax.persistence.FetchType;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.OneToOne;
import javax.persistence.Table;

import org.hibernate.annotations.AccessType;

/**
 * object model for the view [InvestmentReturn].[vMAE_MFE]
 */
@Entity
@Table(name="vMAE_MFE", schema="InvestmentReturn")
@AccessType("field")
public class MAE_MFEView
{
    /**
     * trade property is a SuggestdTradeRecommendation object
     */
    @Id
    @OneToOne(fetch = FetchType.LAZY , cascade = { CascadeType.PERSIST })
    @JoinColumn(name = "suggestedTradeRecommendationID")
    private SuggestedTradeRecommendation trade;

    /**
     * Most Adeverse Excursion value
     */
    private int MAE;

    public int getMAE()
    {
        return MAE;
    }

    /**
     * Most Favorable Excursion value
     */
    private int MFE;

    public int getMFE()
    {
        return MFE;
    }

    /**
     * @return trade property
     * see #trade
     */
    public SuggestedTradeRecommendation getTrade()
    {
        return trade;
    }
}

그러나 지금이 예외가 발생합니다.

Caused by: org.hibernate.MappingException: Could not determine type for: com.domain.idea.SuggestedTradeRecommendation, at table: vMAE_MFE, for columns: [org.hibernate.mapping.Column(trade)]
    at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:292)
    at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:276)
    at org.hibernate.mapping.RootClass.validate(RootClass.java:216)
    at org.hibernate.cfg.Configuration.validate(Configuration.java:1135)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1320)
    at org.hibernate.cfg.AnnotationConfiguration.buildSessionFactory(AnnotationConfiguration.java:867)
    at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:669)
    ... 145 more

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로 표시된 필드가 누락되었습니다

@Id

. 각각

@Entity

은

@Id

-데이터베이스의 기본 키입니다.엔터티를 별도의 테이블에 유지하지 않고 다른 엔터티의 일부로 유지하려는 경우

@Embeddable

대신 대신 사용할 수 있습니다

@Entity

.단순히 데이터 전송 객체가 최대 절전 모드 엔터티의 일부 데이터를 보유하도록하려면 아무 주석도 사용하지 마십시오. 단순한 포조로 두십시오.업데이트 : SQL 뷰와 관련하여 Hibernate 문서는 다음과 같이 작성합니다.

There is no difference between a view and a base table for a Hibernate mapping. This is transparent at the database level

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For me, javax.persistence.Id should be used instead of org.springframework.data.annotation.Id. For anyone who encountered this issue, you can check if you imported the right Id class.

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This error can be thrown when you import a different library for @Id than Javax.persistance.Id ; You might need to pay attention this case too

In my case I had

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Table;

import org.springframework.data.annotation.Id;

@Entity
public class Status {

    @Id
    @GeneratedValue
    private int id;

when I change the code like this, it got worked

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Table;

import javax.persistence.Id;

@Entity
public class Status {

    @Id
    @GeneratedValue
    private int id;

---

The code below can solve the NullPointerException.

@Id
@GeneratedValue
@Column(name = "STOCK_ID", unique = true, nullable = false)
public Integer getStockId() {
    return this.stockId;
}
public void setStockId(Integer stockId) {
    this.stockId = stockId;
}

If you add @Id, then you can declare some more like as above declared method.

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I know sounds crazy but I received such error because I forget to remove

private static final long serialVersionUID = 1L;

automatically generated by Eclipse JPA tool when a table to entities transformation I've done.

Removing the line above that solved the issue

참고URL : https://stackoverflow.com/questions/4381290/hibernate-exception-org-hibernate-annotationexception-no-identifier-specified